solve : 1- sin^2 135
Isn't there some more info; write down the problem as given.
Given is equal to Cos^2 135 = Cos^2 (90 + 45) That help?
no , the question is to choose the correct answer : 1)0 . 2) -1 3)1
1/2
please explain how u got 1\2
\[135\approx \pi/4\]
\[1-\sin^2135=1-(\sin135)(\sin135)=\]\[1-(0.707...)^2=1/2\]
without using calculator !!
Without calculate it is angle pi/4, same thing.
Given is equal to Cos^2 135 = Cos^2 (180 - 45) = -Cos^2 (45) = 1/2
1- sin^2 135 = 1- sin^2(3pi/4)=cos^2 (3pi/4)=(1+cos (2*3pi/4))/2=(1+cos(3pi/2))/2=(1+0)/2 = 1/2
thank you all for your help ...
you're welcom
okay. sin 135=sin45. The sine curve is symmetrical about 90 degrees. So you now have a triangle with hypotenuse=1 and two equal side (because the angle is 45 degrees). So:\[1^2=(1/\sqrt{2})^2+(1/\sqrt{2})^2\]So each side is of length \[1/\sqrt{2}\]Thus the sine of the angle is \[\sin 135=\sin 45=(1/\sqrt{2})/1=1/\sqrt{2}\]and \[1-\sin^2135=1-(1/\sqrt{2})^2=1/2\]
If you use Cos^2 + Sin^2 = 1 and Cos (pi-t) = - Cos t, the answer follows.
sorry , in fact the question is 1-2 sin^2 135 . so i didn't write 1\2 in the choose but i got the idea , thanks
lol. then answer is 0
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