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Kepler’s law states that if one object is in orbit around another, the square of the time it takes that object to complete a revolution varies directly with the cube of the average radius of the orbit. How is the time affected if the average radius is doubled?

Question

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	Kepler’s law states that if one object is in orbit around another, the square of the time it takes that object to complete a revolution varies directly with the cube of the average radius of the orbit. How is the time affected if the average radius is doubled?

tad1 · Answer

kepler's Law t^2 = kr^3
so if r is doubled the right hand side would be k(2r)^3; so t^2 would be 8 times as big, and t would be sq rt of 8  = 2 sq rt 2  times longer

anonymous · Answer

so would the answer be 8t then...?

tad1 · Answer

(sq rt of 8)t