Question

the derivitve of ln(1-3x)

Answer 1

d/dx (log(1-3x))
= 3/3x-1

Answer 2

ln(1-3x) its derivative
1/(1-3x) * -3=-3/(-3x+1)

Answer 3

Because ln(1-3x) follows the form ln u, you'll need to use the chain rule. Like Nick said, you multiply d/dx (ln u) by u'. If you take the derivative of u = 1-3x, you get -3. So -3*(1/1-3x) = d/dx[ln (1-3x)]

Answer 4

...Did you post that in the right place, Kyleigh?