How long will it take to discharge a 10μF capacitor from 10V to zero if the current through the capacitor is constant and equal to 2A ?
q=Cv
Thank you.
something along those lines
wait that question is dodgy
current cant be constant through a capacitor
wait , take back what I said
\[i= c \frac{dv}{dt}\]
\[c \frac{dv}{dt} = 2 \]
divide both sides by c , integrate, use the initial condition to find the constant of integration
etc
2 amperes represent 2 coulombs/sec. Since there is only 10^-4 coulomb of charge, if the currents was constant, the capacitor would be completely discharged in 50 micro seconds.
\[v = \frac{2t}{c} +D\] where D is integration constant, which is 10 from the initial condition
O.K.Thank you.
The amount of charge was computed from the equation provided by elecengr above. Q=CV where Q is charge in Coulombs, C is Capacitancer in farads, v voltage in volts.
\[Q=10volts x 10 x 10^{-6} farads=10^{-4}Coulombs\]
O.K.Thank you radar.
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