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Mathematics 19 Online
OpenStudy (anonymous):

find the asymptotes of y=(4x+2)/(x+2)

OpenStudy (tad1):

vertical asymptote at x = -2

OpenStudy (saifoo.khan):

line pareel to y-axis

OpenStudy (saifoo.khan):

parellel*

OpenStudy (anonymous):

if x=-2, the y should be 4, according the the m.c. answers given. the other y when x=-2 is -1/2 and i know that's incorrect. anyway someone could explain it a bit more?

OpenStudy (anonymous):

vertical asympote at x = -2, horizontal at y = 4

OpenStudy (anonymous):

easy to check for horizontal asymptote. the degree of the numerator in this example is equal degree of the denominator to horizontal asymptote is y = ratio of leading coefficients, in this case 4/1

OpenStudy (anonymous):

if degree of numerator is larger no horizontal asympote. if degree of denominator is larger then horizontal asmptote is y = 0

OpenStudy (anonymous):

i don't know if you need any further explanation, but those are the simple rules

OpenStudy (anonymous):

thanks! im in the process of teaching myself calc, so all of this prelim stuff is coming back when people start explaining it.

OpenStudy (anonymous):

teaching yourself calc? have fun!

OpenStudy (anonymous):

hahah not voluntarily. i need an A or B in calc to transfer to a different university

OpenStudy (anonymous):

good luck

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