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OpenStudy (anonymous):
A polynomial f(x) with real coefficients and leading coefficient 1 has zeros -7, 0, 1 + i and degree 4. Express f(x) as a product of linear and quadratic polynomials with real coefficients that are irreducible over IR. (Another one, I tried but it didn't work)
15 years ago
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OpenStudy (anonymous):
f(x)= x(x+7)(x -1- i)(x -1 +i )
f(x) = x(x+7)[(x-1)^2 - i^2]
f(x)= x(x+7)[(x-1)^2 +1)
f(x)= x(x+7)(x^2 -2x +1 +1)
f(x) x(x+7)(x^2 -2x +2)
15 years ago
OpenStudy (anonymous):
Thanks!
15 years ago
OpenStudy (anonymous):
its probably a lack of brackets in your working out that is causing the mistakes lol
15 years ago
OpenStudy (anonymous):
Probably :)
15 years ago
OpenStudy (anonymous):
yes, bracket is pretty important here :D
15 years ago
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OpenStudy (anonymous):
if 1+i is a root then so is 1-i
15 years ago
OpenStudy (anonymous):
f(x) = z (z-+7)(z - (1+i) ) (x- (1-i) )
15 years ago
OpenStudy (anonymous):
you probably need to put the brackets inside brackets , im guessing you are forgetting a minus sign when expanding
15 years ago
OpenStudy (anonymous):
why did I put z and x :|
15 years ago
OpenStudy (anonymous):
Yep, that's where it went wrong!
15 years ago
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OpenStudy (anonymous):
lol lol, z and x...variables are always painful, we don't want more of that :D
15 years ago
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