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Mark all ordered pairs which ARE a solution for y < 3 - 2x. A. (0, 4) B. (-1, 3) C. (6, -8) D. (-4, 5)
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i got a,c, and d
Ok, so lets look at a. \[4 < 3 - 2(0)\] \[\implies 4 < 3\] Is that true?
no
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All we're doing is plugging in our (x,y) pair into the inequality: y < 3-2x Then we see if the inequality holds true. So if y is 4 and x is 0, then we get 4 < 3 - 2(0) Which simplifies to 4 < 3 which isn't true, so a isn't a solution.
Now you try it for b
ok
ok i got my answer i get it thx
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