Write an equation of the line containing the specified point and perpendicular to the indicated line (4, −2), x = 1
http://bit.ly/lMbO9w x=1 is a vertical line. The perpendicular line must be horizontal, of the form y=c, where c is a constant. if it must pass through (4,-2), the equation must be y = -2.
this is what my instructor wrote to the other student with the same problem...The slope is not correct. x = 1 is a vertical line so the line perpendicular to it is a horizontal line. The slope of a horizontal line is 0. she wrote y=1x-2
so is that sayin the same thing? that y=-2? i dont get it
did you look at the link? It shows the two lines and the point.
oh no let me look
i only see a blank graph
there's no red line and blue line? and blue point?
no
OK. Anyway. what do you not understand about my explanation? It seems to mesh with what your instructor is saying...
well i dont know how to write the equation. is it y=-2? and what were the steps to get there?
it's all in my explanation. your original line is x = 1, which is a vertical line, parallel to the y axis, one unit away. so the perpendicular line must be horizontal. horizontal lines have zero slope. if you use the "y = mx + b" equation, and substitute "0" for the slope (m), you get "y = 0x + b" or "y = b". Meaning y = a constant. If you want this line to pass through the point (4,-2), then the constant has to be equal to the y coordinate of the point, or -2. This means the equation must be y = -2.
it's more intuitive if you plot the x=1 and the point on some graph paper.
so if x=1 and y=-2 how is the slope 0?
slope is change in y over change in x. in the equation "y = -2", take two points on the line and calculate the slope with (y1 - y0) / (x1 - x0). You will get the answer zero. or use the "y = mx + b" equation, where m is slope. In the equation "y = -2", m equals zero.
by definition, a horizontal line has slope of zero because there is no change in y. it is a constant.
the slope of x=1 is really undefined. normally you can take the negative reciprocal of a line's slope to get the slope of the perpendicular, EXCEPT with vertical / horizontal, which you must treat as special cases to avoid division by zero.
have you had an epiphany? :-)
ok i think i got it..lol thanks a bunch hope to see ya on my next problem..lol i have my final due by sunday and Lord willing I pass and am done with math..oh wait..i still have intemediate algebra to do!! arrgggg
Lord has nothing to do with it. Believe in yourself! :-)
I can do all things through Christ who strengthens me! Thanks for your help and have a great night!
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