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Mathematics 20 Online
OpenStudy (anonymous):

3y-2=4; 2

OpenStudy (anonymous):

???????

OpenStudy (anonymous):

There is no question, or instructions here.

OpenStudy (anonymous):

3y-2=4 3y=4+2 3y=6 y=2

OpenStudy (anonymous):

it sais determine if the givin number is a solution to the equation.

OpenStudy (anonymous):

yes the given no is a solution

OpenStudy (anonymous):

for 3y-2=4 ; 2?

OpenStudy (anonymous):

this is homework and im so lost

OpenStudy (anonymous):

its a solution because 3(2) =6; 6-2 = 4; 2 is a solution.

OpenStudy (anonymous):

thus 3y-2 = 4; y = 2

OpenStudy (anonymous):

3y-2=4 3(2) - 2 = 4 6-2= 4 4 = 4 therefore yes the given number is the solution to the equation

OpenStudy (anonymous):

Any value for 'y' that satisfies the equation is a solution i.e. on putting that value into the equation the left hand side and right hand side of the equation should be same. In above problem on putting y=2 you have, 3(2)-2=4 =>6-2=4 =>4=4 both the sides have same value and hence 2is the solution.

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