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Mathematics 23 Online
OpenStudy (anonymous):

if 00 (b)s<-1 and t<-1 (c)s>1 and t<-1 (d) s>-1 and t<-1 (e)s>1 and t>1

OpenStudy (anonymous):

a. canr be true

OpenStudy (anonymous):

i don't get any of these choices s and t both have to be positive or t they both have to be negative

OpenStudy (anonymous):

can or cant?

OpenStudy (anonymous):

cant

OpenStudy (anonymous):

b is out as well

OpenStudy (anonymous):

they are all out actually

OpenStudy (anonymous):

they both need specific intervals

OpenStudy (anonymous):

instead there are no boundaries on any choices, so they are al wrong

OpenStudy (anonymous):

it says the answer is d it doesnt make sense

OpenStudy (anonymous):

what you saying makes sense but the choices dont

OpenStudy (anonymous):

thats wrong

OpenStudy (anonymous):

what about s=1000 , and t= -100

OpenStudy (anonymous):

oops it said C but i still dont see it

OpenStudy (anonymous):

data insufficient.....

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

I think C should say s>-1 and t<-1....then it would be right... (a) is wrong, since one number would be negative and the other positive, so their product would be negative, and thus not between 0 and 1. (b) is wrong, since their product will always be a positive number greater than 1. (d) is wrong for the same reason as (a). (e) is wrong for the same reason as (b).

OpenStudy (anonymous):

^ no it wouldnt

OpenStudy (anonymous):

s=100 , t= -1000 that fits in that condition but their product isnt between 0 and 1

OpenStudy (anonymous):

Right, but read the question...CAN be true...

OpenStudy (anonymous):

s=-0.5, t=-1.5...product is 0.75

OpenStudy (anonymous):

Again, this is only for s>-1, t<-1

OpenStudy (anonymous):

so d would be correct because we could do t=-.5 and s=-1.5 s<-1 and t>-1

OpenStudy (anonymous):

True...sorry, I looked at (d) incorrectly...it was late :) Yes, D is the right answer. It is exactly what I described, I just didn't see that d matched it. C is incorrect because the product is a negative number. My mistake.

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