Question

WHAT about this one
solve for x
uploaded

Answer 1

X^2/x+3=4

X^2=(x+3)*4

X^2=4x+12

X^2-4-12=0

(X-6)(x+2)

x=6,-2

Answer 2

\[\log _{2}x ^{2} - \log_{2}(x+3) =2\]
\[\log_{2}(x^{2}/ (x+3) ) =2\]
\[x^2/ (x+3) = 2^2 = 4 \]

x^2 = 4(x+3)
x^2= 4x +12
x^2 -4x -12= 0
(x-6)(x+2) = 0 => x=6, x=-2

Answer 3

^ incorrect.

x = -2 is not a solution, since logarithms of negative numbers aren't real numbers.

x = 6

Answer 4

it's one of the solution, but forgot the step of condition, and we have to test it after we get the solutions to pick up which one will work :) ...hello James

Answer 5

yep, it's an extraneous solution

log2(-2) is undefined