Question

Spanning sets?? Linear algebra, anyone?!!

Answer 1

Did you try downloading the linear algebra link I sent you?

Answer 2

yea it doesn't help with spanning sets..

Answer 3

I see...well, I may be able to help you even though I know nothing about linear algebra...lol...I'll see what I can do...

Answer 4

Here's the problem, somebody help!

Answer 5

standby...

Answer 6

estudier, finally some linear algebra help is here.. Can you help me out?

Answer 7

row reducing....matix..

Answer 8

lol, what's that?

Answer 9

i think i got it..

Answer 10

I see something... if I get this right again.. it will be the second time I posted the question and solved it haha.. Why don't people ever answer my questions correct on here.........-.-......................................... amistre helped me out like once and that was it...

Answer 11

strange, he helps everybody, I don't know why he isn't helping you...

Answer 12

I asked him, he said he's not good at lin algebra..

Answer 13

I see..

Answer 14

I can help you but you may have to pay me afterwards.

Answer 15

you know what hero.. i doubt it.. i haven't noticed any of your "outstanding" math skills yet..

Answer 16

Ok, start by solving for the individual subspaces (column, row, null). Are you familiar with how to do that part?

Answer 17

Well right now I found what was this stuff:
R(A) = the basic columns in A
R(A transpose) = the non-zero rows

Answer 18

and apparently you write those non zero rows as columns..

Answer 19

Yeah, that's mostly right. You have to reduce the matrix first.

Answer 20

yea I got the right answers for R(A) and R(A^t).. now how do ifind the rest?

Answer 21

Nullspace and left-hand nullspace?

Answer 22

Once you have the matrix reduced, the non-zero rows will be the columns of the row-space of A.

Also any pivot columns will indicate which of the columns of A form a basis of the column space.

Answer 23

The null-space of A is just the solutions to:

Ax = 0

Answer 24

okay.. standby ima figure out the soln's real quick..

Answer 25

wait how many Xs do I put? x1 x2 and x3?

Answer 26

i mean, is the number of xs that i need to find the same as the number of rows or the number of columns?

Answer 27

Well you have a matrix with 5 columns, so the number of rows in your x vector must be 5 also.

Answer 28

(3x5)(5x1) = 3x1

Answer 29

but wait what about the bottom? Do I just put 0s there?

Answer 30

http://www.twiddla.com/563528
Can you go here, so that I can explain what I mean?