Question

stumped on another one! 3sqrt x-4=2 solve algebraically

Answer 1

cube both side, resulting in x-4=2^3, which then gives you: x-4=8. Finally add 4 to both sides giving you: x=12

Answer 2

umath has it if you mean
\[\sqrt[3]{x-4}=2\]

Answer 3

if you meant
\[3\sqrt{x-4}=2\] however the answer would be different. i assume you meant the first one

Answer 4

Umath has the right equation. I am trying to figure it out righrt now to see if it works

Answer 5

I missed one step on this one!

Answer 6

\[(\sqrt[3]{x-4?})^{3}=2^{3}\]

Answer 7

\[x-4=8\]\[x=8+4\]\[x=12\]

Answer 8

check\[\sqrt[3]{12-4}=\sqrt[3]{8}\]\[\sqrt[3]{2*2*2}=2\]