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is this the correct answer? 2a^4m-32b^8m 2(a^4m-16b^8m)
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factor out the m as well. then you can go further because you have the difference of two squares
step one \[2m(a^4-16b^8)\]
step two \[2m(a^2-4b^4)(a^2+4b^4)\]
step 3 \[2m(a-2b)(a+2b)(a^2+4b^4)\]
twice we used factoring the "difference of two squares" \[x^2-y^2=(x+y)(x-y)\]
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