Question

need the step by step please.
x^2-3x-1=0

Answer 1

use the quadratic formula

Answer 2

x*2 -3x -1 =0
3 +/- radical ( (-3)*2 - 4(1)(-1) ) 3 +/- radical (9+4)
x_1,_2 =-------------------------- = ---------------- =
2(1) 2
3 +/- radical 13
= ---------------
2

Answer 3

\[-b+or-\sqrt{b^2-4ac}\]
---------------------
\[2a\]

Answer 4

she said step by step....lol

Answer 5

well you have to try it atleast you have the formula

Answer 6

use
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
put
\[a=1,b=-3,c=-1\] get
\[\frac{-(-3)\pm\sqrt{(-3)^2-4\times 1\times -1}}{2\times 1}\]

Answer 7

this gives
\[\frac{9\pm\sqrt{9+4}}{2}\]

Answer 8

which in turn gives
\[\frac{9\pm\sqrt{13}}{2}\] and that is your answer

Answer 9

step by step

Answer 10

That's much better, lol

Answer 11

hey satellite73 thos are not correct solutions

Answer 12

please check you newly

Answer 13

jhonny is right

Answer 14

at least he presented step by step, but lol

Answer 15

ty heromiles

Answer 16

I hope levie isn't confused by any of this...lol