Question

find the locus of the point P(x,y) which moves so that its perpendicular distance from 3x+4y=0 is always equal to its perpendicular distance from 5x-12y=0

Answer 1

Do i find the perpendicular distance of both sides, and set the two to equal? and then solve from there?

Answer 2

yes

Answer 3

\[\frac{|3x+4y|}{\sqrt{3^2+4^2}}\]=\[\frac{|5x-12y|}{\sqrt{5^2+(-12)}}\]

Answer 4

Great!....Thanks again

Answer 5

(-12)^2

Answer 6

you're welcome!