Find the distance between the two parallel lines: Line x+y=1 Line x+y=5
4units
How did you to arrive at that?
y=-x+1 y=-x+5 Since they are same slope, we know that they are parellel
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Parallel means distance is the same everywhere
So we may use any point on either line to calculate distance. Let use x=0 on both Plugging in 0 for x y=1 y=5 as you can see the difference is 4
the distance between the lines is the length of the perp that connects the,
measuring a diagonal doesnt tell us a thing except for that diagonally they can be any distance apart lol
x+y=1; modyfy one of the equations to get the perp equation x-y = n; now calibrate it with one of the y intercepts since we know those are on either line
Lol....now i'm confused...but thanks all..i'll continure to work at it n see how it goes
continue*
(0,1) is as good a point as any x-y = n; at (0,1) = 0-1 = -1 the equation for the perp is then x-y = -1 use this equation to find the solution to the perp and the 'other' parallel line
x+y = 5 x -y =-1 ------- 2x = 4; when x=2 x+y = 5; when x=2, y=3 (0,1) and (2,5) are 2 points, one on each line, that are perpedicularlly across from each other
subtract one point from the other and add them together then sqrt them :)
this make any sense to ya?
I was wondering if it was simultaneous from the start! lol...n yeah it makes alot of sense now...Thanks! :)
i get x=2 apart; y=4 apart sqrt(2^2 + 4^2) = sqrt(20) = 2sqrt(5) if I did it right ;)
k i'm workin out now..let me check
oh i jus see what you had...it's x+y=1 ..so i'll work out from there
ugh, i read 3 as a 5; but the concept the same even tho the numbers are typoed lol
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