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The integral of xcscxcotxdx
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–csc x + C
\[\int [csc(x)cot(x)]\ x\ dx)\]
You can use integration by parts. Let u=x and du=csc(x)cot(x) Then you have u=x dv=csc(x)cot(x)dx du=dx v=-csc(x) So you have -csc(x)x-S(-csc(x))dx \[-x \csc(x)+\int\limits \csc(x)dx=-x \csc(x)-\ln|\csc(x)+\cot(x)|+C\]
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