the integral of sin sqrt of x / sqrt of x dx
This one is slightly more difficult. Have you done u-substitution?
\[\int\limits_{}^{} \sin \sqrt{x} / \sqrt{x}\]
hold on. i'll try, i'll post a question if anything confuses me. lol. :)
Okay :P
can i rewrite this as \[\int\limits_{}^{} \sin x^{1/2}/x^{1/2}\]
Yes. What next?
can i use power rule at sin x^1/2 then use sin rule? xD
You have to use u-substitution. So let: \[u=\sqrt{x}\] Then the derivative of that is: \[du=\frac{1}{2}\frac{1}{\sqrt{x}}dx\] So replace those in your integral and get: \[2 \int\limits \sin(u) du\] Which is \[-2\cos(u)+C\] Rewrite in terms of x. \[u=\sqrt{x} \rightarrow -2\cos(\sqrt{x})+C\] Which is your final answer.
wow! thank you sir! i'll try solving this to understand it further. :p
Okay, just tell me if you get lost :P Integration is sort of my forte :P
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