Question

Simplify Square root of 50 + square root of 128.

Answer 1

Note that 50 = 25*2, so
\[\sqrt{50} = 5\sqrt{2}\]
Also, 128 = 64*2, so
\[\sqrt{128} = 8\sqrt{2}\]
Thus,
\[\sqrt{50} + \sqrt{128}\]
\[= 5\sqrt{2} + 8\sqrt{2}\]
Gathering like terms,
\[= 13\sqrt{2} \]