This is trigonometry question. You board the London ferris wheel. graph h=f(t), your height in feet above ground t minutes after the wheel begins to turn. Label the period, the amplitutde, and the midline of each graph, as well as both axes. In each case, first determine an appropriate interval for t, with t greater than or equal to 0. 13. The london ferris whell has increased its rotation speed. the whell completes one full revolution every ten minutes. you get off when you reach the ground after having made two complete revolutions. the ferris wheel is 450ft in diameter and turns around onc
if it completes one revolution in ten minutes, period is 10 minutes. the amplitude will be the radius of the ferris wheel, which is 225ft for q13 the midline of the graph will be 225feet as well. the interval for t will be [0,20] if you do 2 revolutions
the height of the ferris wheel in q13 can be modelled by h(t) = 225sin(pi*t/5) + 225
where did you get the t/5. Sorry my instructor is lame at giving details at how to do this. I've got no idea how to do any of it.
oops, sorry: h(t) = -225cos(pi*t/5) + 225
the period of cos(nt) is 2pi/n so if 2pi/n = 10, then n = pi/5
and why is it -225cos( ??? it should be just 225cos or not? sorry i'm just curious.
225cos + 225 is if you start at the top of the ferris wheel (h = 450 when t = 0) -225cos + 225 is if you start at the bottom (h = 0 when t = 0), as in q13
i graphed this. and it doesn't start at height 0 when t=0
nevermind. it works.
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