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(10x^6+20x^4-15x^2) ÷5x^2
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factor out the top part.
\[\frac{1}{5x^2}10x^6+20x^4-15x^2\]
or just divide each term separately by dividing the numbers by 5 and subtracting the exponents
5x^2 cancels at top and bottom leaving 2x^4 + 4x^2+3
if someone comes up with the answer jus put it on here please!
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for example 10/5 = 2 and \[\frac{x^6}{x^2}=x^{6-2}=x^4\] so first term is \[2x^4\] and work your way down the line
\[\frac{10x^6}{5x^2}=2x^4\] \[\frac{20x^4}{5x^2}=4x^2\] \[\frac{-15x^2}{x^2}=-3\]
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