Question

A ball is dropped from a treetop 256 feet above the ground. How long does it take to hit the ground? (s = 16t^2)

4 seconds
8 seconds
16 seconds

Answer 1

what is (s=16t^2) ??????

Answer 2

\[s=16t^{2} \]

Answer 3

s = distance right? lol

Answer 4

Ok, I understood what they hv done, divided value of g(in ft) by 2....

In this case distance "s" is given by the formula
s = ut + 1/2gt^2

here u = initial velocity = 0 (so ut = 0)
g = acceleration due to gravity = 32 ft/s^2 (second^2)
t = ? we have to find out
So let time = t s ie. t second
putting these values in the formula
s = 0*t + 0.5*32*t^2 ft/s^2
256 = 16 t^2
256/16 = t^2
16 = t^2
root(16) = t
4 = t

Answer 5

so ans is 4 second

Answer 6

\[256=16t^2\]\[t^2=\frac{256}{16}\]\[t=\sqrt{16}=4 \]

Answer 7

hey willow,
pls click GOOD ANSWER button if u r satisfied with the answer :))