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what are my solutions if i get 4 as my discriminate
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The two possible square roots are 2 & -2. So the solutions will be: \(\frac{-b\pm2}{2a}\).
our teacher wants us to put 2 complex 2 real what is the difference between them
Huh? This equation doesn't have any complex solutions.
so it will be 2 real
Yes.
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what will make it a complex solution
If discriminant is positive: 2 real. If zero: 1 real. If negative: 2 complex.
thanks
No problem.
wait will it always be 2 complex if it is negative
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Yeah, say for example you get \(\sqrt{-4}\) as your discriminant. The two possible values of this are 2i and -2i.
good point thanks
You're welcome :)
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