Question

what are the variables for a qudratic equation

Answer 1

?

Answer 2

if i had the equation x^2+4X+3

Answer 3

x

Answer 4

a=
b=
c=

Answer 5

a = 1
b = 4
c = 3

the general form is ax + by + c

Answer 6

a=1
b=4
c=3

Answer 7

actually general form is
\[ax^2+bx+c=0\]

Answer 8

ya sorry I've been working in different planes lately, mixed up my variables

Answer 9

thats what i thoght
-x^2-x=4 find the discriminate
but my textbook says the answer is -15

Answer 10

i get -17 2 complex
not -15 2 imaginary
what am i doing wrong

Answer 11

\[(-b \pm \sqrt{b^2-4ac})/2a\] as far as I remember, the part under the square root is your discriminate, which should be 16-12 = 4, which gives roots -1 and -3, complex numbers shouldn't play into this equation

Answer 12

no i worte that as a equation in the book

Answer 13

oh you're referring to -x^2 - x = 4, sorry my mistake, one second

Answer 14

yea

Answer 15

as far as i know if you get:
Negative = 2 Complex
Zero = 1 Real
Positive = 2 Real

Answer 16

you should get \[(1\pm i \sqrt{15})/2\]

Answer 17

were do i use an imginary

Answer 18

how

Answer 19

first you bring everything over to one side so you're equation becomes x^2+x+4 = 0
then you plug it into the quadratic equation using a = 1, b = 1, c = 4

Answer 20

discriminanat is b^2 - 4ac
= (-1)^2 - 4(-1)(-4)
= 1 - 16
= -15

so the ans in the book is right !!!!

Answer 21

shouldent it be negative 4

Answer 22

discriminant is just value of b^2 - 4ac

the formula u r using is for finding the roots in which the discriminant occurs as a part...

Answer 23

ya I just did the whole process, the discriminate is -15

Answer 24

in my calculator i forgot to put parenthesis on the one duh

Answer 25

-x^2-x=4 find the discriminate <---- This yr question???

Answer 26

but still shouldent it be 2 complex since it is a negative

Answer 27

writing in standard form it becomes -x^2 - x -4 = 0
so a = -1, b = -1 and c = -4
so b^2 - 4ac = (-1)^2 - 4(-1)(-4) = 1 - 4(4) = 1 - 16 = -15

Answer 28

the discriminate is everything under the square root, but not including the square root itself
so no complex numbers

Answer 29

why r u taking its root????

Answer 30

discriminant is just value of b^2-4ac !!!

Answer 31

that's why I just said, everything UNDER the square root but NOT including the square root

Answer 32

of the quadratic equation

Answer 33

\[-x^2-x=4\]
\[x^2+x+4=0\]
\[b^2-4ac=1-16=-15\] that is the discriminant

Answer 34

that is what i have already told him....

Answer 35

i know the discrimnate but we also need to put what you will get, as far as i know if you get: Negative = 2 Complex Zero = 1 Real Positive = 2 Real our book says discriminnate -15 and 2 imaginary solutions

Answer 36

when do you put imaginary solutions

Answer 37

now
when value of D >0 i.e positive, you get two distinct real roots
when value of D=0, you get two equal roots, ie. one solution
when value of D<0, i.e negative, you get two imaginary roots

Answer 38

you do have 2 imaginary solutions, the ones I initially stated, who's discriminate is -15

Answer 39

D means discriminant
in your case D<0 i.e. negative so you will get two imaginary roots

Answer 40

ur roots are (-1+i*sqrt(15))/2 and (-1-i*sqrt(15))/2 which are both imaginary

Answer 41

so complex is the same as imaginary

Answer 42

complex and imaginary mean the same thing....

Answer 43

ya complex means imaginary

Answer 44

thanks

Answer 45

i is the imaginary number that only exists in the complex plane C, which was created for the purpose of handling the imaginary number :p

Answer 46

no problem, hope that wasn't too confusing