Question

Find the length of the hypotenuse of a right triangle whose legs are 5 and squareroot(2).

2squareroot(3)
3squareroot(3)
squareroot(29)

Answer 1

its multiple choice (:

Answer 2

hypothenus are found by
Sqrt[x^2+y^2]=h

Answer 3

Sqrt[5^2+(sqrt[2])^2]

sqrt[27]

Answer 4

sqrt[27]=3sqrt[3]

Answer 5

\[a^2 + b^2 = c^2\]

Where a and b are the length of the legs and c is the length of the hypotenuse. Solve for c.

Answer 6

sqrt (5^2 + 2)

Answer 7

\[\sqrt{5^2+\sqrt{2}^2}=\sqrt{25+2}=\sqrt{27}\]\]

Answer 8

and since
\[27=3^3\] you have
\[\sqrt{3^3}=3\sqrt{3}\]

Answer 9

so answer is second one