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Mathematics 16 Online
OpenStudy (anonymous):

can someone explain to me how you know when you need to put and i (imaginary) into your answer when you are solving symbolically in standard form. ex: x^2+9=0

OpenStudy (anonymous):

Sure, I can assist.

OpenStudy (anonymous):

When you use the quadratic equation, and you get a negative number inside of the determinant (the part that has the square root), you will need to use an i

OpenStudy (dumbcow):

i is just a way for math people to deal with a negative number inside of a square root i = sqrt(-1)

OpenStudy (anonymous):

Does that make sense? Or would like an example answer?

OpenStudy (anonymous):

that really does help a lot. could you give me an example though?

OpenStudy (anonymous):

Of course. Let's use your x^2 + 9 example

OpenStudy (dumbcow):

so sqrt(-16) = sqrt(16)(sqrt(-1) = 4i

OpenStudy (anonymous):

First, I need to know two things: Do you know how to use the quadratic formula?

OpenStudy (anonymous):

yes i do

OpenStudy (anonymous):

Awesome! So what is A,B and C in x^2 + 9?

OpenStudy (anonymous):

okay so i'm a little confused since there are only two sets. i know i probably sound really dumb!

OpenStudy (anonymous):

Nah... don't worry about it! We all have to start somewhere! I prefer to explain slowly and take the long way to the answer as opposed to just saying what the answer is. So this is perfect.

OpenStudy (anonymous):

We can agree that A, B and C are normally used this way: Ax^2 + Bx + C Right?

OpenStudy (anonymous):

haha that's exactly what i need, so thank you (:

OpenStudy (anonymous):

yeah that makes sense

OpenStudy (anonymous):

Alright! So our problem is: X^2 + 9

OpenStudy (anonymous):

Pick any of the letters that you already know. (Hint: I think you know what C is)

OpenStudy (anonymous):

c=9?

OpenStudy (anonymous):

Perfect! C is always the number without the X.

OpenStudy (anonymous):

sweet. so is a=x^2?

OpenStudy (anonymous):

perfect!

OpenStudy (anonymous):

So this leaves us with a mysterious B that we can't see. I'll give you a hint: B technically exists. But we just ignore it. So what is B most likely? In other words, how many X's do we have (note that we don't care about X^2. Just X by itself).

OpenStudy (anonymous):

Oh wait... I said something wrong. I meant to say "A is linked to x^2" I'll explain that some more in a moment.

OpenStudy (anonymous):

is it 0?

OpenStudy (anonymous):

perfect!

OpenStudy (anonymous):

Ok, earlier I meant to say that A doesn't equal X^2, but rather, that it is related to x^2. How many X^2 do we have in x^2 + 9?

OpenStudy (anonymous):

1

OpenStudy (anonymous):

bingo!

OpenStudy (anonymous):

So, our formula, when expanded, is actually: 1x^2 + 0x + 9

OpenStudy (anonymous):

Does this make sense? If not, do ask.

OpenStudy (anonymous):

yes it does completely

OpenStudy (anonymous):

Awesome! Just to make sure: could you tell me A,B,C in: 3x^2 - 4x ?

OpenStudy (anonymous):

a=3 b=0 c=4

OpenStudy (anonymous):

Close. But remember: C is always the number by itself, and B is always next to the X. So it's Ax^2 + Bx + C

OpenStudy (anonymous):

So try that question again. 3x^2 - 4x

OpenStudy (anonymous):

right so a=3 b=4 and c=0

OpenStudy (anonymous):

Close again. You forgot a sign. ;)

OpenStudy (anonymous):

ahhh -4

OpenStudy (anonymous):

Yup!

OpenStudy (anonymous):

Alright, so I think you've got the letters down. Now let's go back to your original question: x^2 + 9 Remind me of our A,B,C on this question.

OpenStudy (anonymous):

okay a=1 b=0 c=9

OpenStudy (anonymous):

Perfect! Now, do you remember the quadratic equation? Could you post it for me?

OpenStudy (anonymous):

b^2 +/- square root4ac/2a

OpenStudy (anonymous):

4ab

OpenStudy (anonymous):

Actually it's -b + or - the square root of b^2 - 4ac, all divided by 2a

OpenStudy (anonymous):

Do you remember this one?

OpenStudy (anonymous):

yeah kinda, i just don't have the best memory

OpenStudy (anonymous):

it's in my notes though

OpenStudy (anonymous):

Has your teacher told you about the "pop goes the weasel" song to remember it?

OpenStudy (anonymous):

Also known as the "jack in the box" song?

OpenStudy (anonymous):

haha no

OpenStudy (anonymous):

Ah. Do you know how the real pop goes the weasel song sounds?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

Awesome. Just sing this a few times and you'll never forget it again: Negative B.. plus or minus the squareee root of B squared... minus four a c, allll over twoooo a. (like the pop goes the weasel song) :P

OpenStudy (anonymous):

ANYHOW.....

OpenStudy (anonymous):

haha cool, thanks

OpenStudy (anonymous):

-b + - squareroot (b^2 - 4ac) -------------------------- 2a

OpenStudy (anonymous):

Alright, so we know that our A is 1 and our B is 0 (yay!) and our C is 9

OpenStudy (anonymous):

0 + - square root (0 - 4*1*9) --------------------------- 2*1

OpenStudy (anonymous):

Does this make sense so far?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

awesome. Do you recall what the + - means?

OpenStudy (anonymous):

that's where the i comes in, right?

OpenStudy (anonymous):

not really It just means "find the answer you get when you add 0 and the stuff in the square root, and then do it again by subtracting the stuff in the square root"

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

Before we finish up the harder i question, let me show you an easy question: If we were at this point: 9 +- squareroot(25) ------------------- 2*1 Could you tell me what our two answers would be? Hint: square roots are technically exponents, so remember the rules of PEMDAS. Tell me if you haven't been taught PEMDAS/Order of operations.

OpenStudy (anonymous):

7 and 2

OpenStudy (anonymous):

Perfect!

OpenStudy (anonymous):

(:

OpenStudy (anonymous):

Now, here's an i example: what is the square root of negative 25?

OpenStudy (anonymous):

5i

OpenStudy (anonymous):

perfecto!

OpenStudy (anonymous):

And if I told you something like: 0 +- squareroot(-36) ?

OpenStudy (anonymous):

6i and -6i?

OpenStudy (anonymous):

Bingo! And if I asked you to divide both answers by 2?

OpenStudy (anonymous):

3i and -3i?

OpenStudy (anonymous):

You got it, buddy! Now let's do a 'totally different' problem. 0 + - square root (0 - 4*1*9) --------------------------- 2*1 This was what we had left after putting in our a,b,c values. Go ahead and finish it up for me.

OpenStudy (anonymous):

is it 3i and -3i again?

OpenStudy (anonymous):

Yep! Sneaky, aren't I? ;)

OpenStudy (anonymous):

haha (:

OpenStudy (anonymous):

And that's your answer to x^2 + 9! The reason it doesn't have any 'real' answers is because it never touches the X axis (which would USUALLY be the real answer).

OpenStudy (anonymous):

okay, that makes sense. thank you so much for your help, i really appreciate it!!

OpenStudy (anonymous):

No problemo! Would you like to take this one step further and learn WHY that's the answer?

OpenStudy (anonymous):

i would love that, but i have my exam in the morning so i should probably get some sleep, but thank you!

OpenStudy (anonymous):

Haha ok. Good night, then! Feel free to subscribe to me so that you can ask me questions if you have any in the future. Best of luck!

OpenStudy (anonymous):

i will, thank you, i'm going to need it!

OpenStudy (anonymous):

Awesome job uber.

OpenStudy (anonymous):

Thanks polpak, I appreciate it!

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