can someone explain to me how you know when you need to put and i (imaginary) into your answer when you are solving symbolically in standard form. ex: x^2+9=0
Sure, I can assist.
When you use the quadratic equation, and you get a negative number inside of the determinant (the part that has the square root), you will need to use an i
i is just a way for math people to deal with a negative number inside of a square root i = sqrt(-1)
Does that make sense? Or would like an example answer?
that really does help a lot. could you give me an example though?
Of course. Let's use your x^2 + 9 example
so sqrt(-16) = sqrt(16)(sqrt(-1) = 4i
First, I need to know two things: Do you know how to use the quadratic formula?
yes i do
Awesome! So what is A,B and C in x^2 + 9?
okay so i'm a little confused since there are only two sets. i know i probably sound really dumb!
Nah... don't worry about it! We all have to start somewhere! I prefer to explain slowly and take the long way to the answer as opposed to just saying what the answer is. So this is perfect.
We can agree that A, B and C are normally used this way: Ax^2 + Bx + C Right?
haha that's exactly what i need, so thank you (:
yeah that makes sense
Alright! So our problem is: X^2 + 9
Pick any of the letters that you already know. (Hint: I think you know what C is)
c=9?
Perfect! C is always the number without the X.
sweet. so is a=x^2?
perfect!
So this leaves us with a mysterious B that we can't see. I'll give you a hint: B technically exists. But we just ignore it. So what is B most likely? In other words, how many X's do we have (note that we don't care about X^2. Just X by itself).
Oh wait... I said something wrong. I meant to say "A is linked to x^2" I'll explain that some more in a moment.
is it 0?
perfect!
Ok, earlier I meant to say that A doesn't equal X^2, but rather, that it is related to x^2. How many X^2 do we have in x^2 + 9?
1
bingo!
So, our formula, when expanded, is actually: 1x^2 + 0x + 9
Does this make sense? If not, do ask.
yes it does completely
Awesome! Just to make sure: could you tell me A,B,C in: 3x^2 - 4x ?
a=3 b=0 c=4
Close. But remember: C is always the number by itself, and B is always next to the X. So it's Ax^2 + Bx + C
So try that question again. 3x^2 - 4x
right so a=3 b=4 and c=0
Close again. You forgot a sign. ;)
ahhh -4
Yup!
Alright, so I think you've got the letters down. Now let's go back to your original question: x^2 + 9 Remind me of our A,B,C on this question.
okay a=1 b=0 c=9
Perfect! Now, do you remember the quadratic equation? Could you post it for me?
b^2 +/- square root4ac/2a
4ab
Actually it's -b + or - the square root of b^2 - 4ac, all divided by 2a
Do you remember this one?
yeah kinda, i just don't have the best memory
it's in my notes though
Has your teacher told you about the "pop goes the weasel" song to remember it?
Also known as the "jack in the box" song?
haha no
Ah. Do you know how the real pop goes the weasel song sounds?
yeah
Awesome. Just sing this a few times and you'll never forget it again: Negative B.. plus or minus the squareee root of B squared... minus four a c, allll over twoooo a. (like the pop goes the weasel song) :P
ANYHOW.....
haha cool, thanks
-b + - squareroot (b^2 - 4ac) -------------------------- 2a
Alright, so we know that our A is 1 and our B is 0 (yay!) and our C is 9
0 + - square root (0 - 4*1*9) --------------------------- 2*1
Does this make sense so far?
yes
awesome. Do you recall what the + - means?
that's where the i comes in, right?
not really It just means "find the answer you get when you add 0 and the stuff in the square root, and then do it again by subtracting the stuff in the square root"
oh okay
Before we finish up the harder i question, let me show you an easy question: If we were at this point: 9 +- squareroot(25) ------------------- 2*1 Could you tell me what our two answers would be? Hint: square roots are technically exponents, so remember the rules of PEMDAS. Tell me if you haven't been taught PEMDAS/Order of operations.
7 and 2
Perfect!
(:
Now, here's an i example: what is the square root of negative 25?
5i
perfecto!
And if I told you something like: 0 +- squareroot(-36) ?
6i and -6i?
Bingo! And if I asked you to divide both answers by 2?
3i and -3i?
You got it, buddy! Now let's do a 'totally different' problem. 0 + - square root (0 - 4*1*9) --------------------------- 2*1 This was what we had left after putting in our a,b,c values. Go ahead and finish it up for me.
is it 3i and -3i again?
Yep! Sneaky, aren't I? ;)
haha (:
And that's your answer to x^2 + 9! The reason it doesn't have any 'real' answers is because it never touches the X axis (which would USUALLY be the real answer).
okay, that makes sense. thank you so much for your help, i really appreciate it!!
No problemo! Would you like to take this one step further and learn WHY that's the answer?
i would love that, but i have my exam in the morning so i should probably get some sleep, but thank you!
Haha ok. Good night, then! Feel free to subscribe to me so that you can ask me questions if you have any in the future. Best of luck!
i will, thank you, i'm going to need it!
Awesome job uber.
Thanks polpak, I appreciate it!
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