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Mathematics 18 Online
OpenStudy (anonymous):

The decay of a particular radioactive substance is given by the formula----UPLOADED----where t is the time it takes for half of the substance to decay, and N(0) is the initial amount of the substance. Find the half-life of this substance to the nearest thousandth of a year.

OpenStudy (anonymous):

OpenStudy (anonymous):

\[\frac{1}{2}N_{0}=N_{0}e^{-1.8t}\implies e^{-1.8t}=\frac{1}{2}\implies-1.8t=\ln (\frac{1}{2})\implies t=-\frac{\ln(\frac{1}{2})}{1.8}\approx0.385\]

OpenStudy (anonymous):

answer is 0?

OpenStudy (anonymous):

to the nearest thousandth means 3 places to the right of the decimal.

OpenStudy (anonymous):

so wht does that meant to the proble im not getting the right answer

OpenStudy (anonymous):

no, it means the answer as bendt stated above is 0.385

OpenStudy (anonymous):

so thaat answer that is not a choice it is multiple choice

OpenStudy (sriram):

in the given equation t is in what units?

OpenStudy (anonymous):

time right

OpenStudy (anonymous):

----where t is the time it takes for half of the substance to decay

OpenStudy (anonymous):

what are you choices?

OpenStudy (anonymous):

ok never mind haha thanks guys!

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