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OpenStudy (anonymous):
The decay of a particular radioactive substance is given by the formula----UPLOADED----where t is the time it takes for half of the substance to decay, and N(0) is the initial amount of the substance. Find the half-life of this substance to the nearest thousandth of a year.
14 years ago
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OpenStudy (anonymous):
14 years ago
OpenStudy (anonymous):
\[\frac{1}{2}N_{0}=N_{0}e^{-1.8t}\implies e^{-1.8t}=\frac{1}{2}\implies-1.8t=\ln (\frac{1}{2})\implies t=-\frac{\ln(\frac{1}{2})}{1.8}\approx0.385\]
14 years ago
OpenStudy (anonymous):
answer is 0?
14 years ago
OpenStudy (anonymous):
to the nearest thousandth means 3 places to the right of the decimal.
14 years ago
OpenStudy (anonymous):
so wht does that meant to the proble im not getting the right answer
14 years ago
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OpenStudy (anonymous):
no, it means the answer as bendt stated above is 0.385
14 years ago
OpenStudy (anonymous):
so thaat answer that is not a choice it is multiple choice
14 years ago
OpenStudy (sriram):
in the given equation t is in what units?
14 years ago
OpenStudy (anonymous):
time right
14 years ago
OpenStudy (anonymous):
----where t is the time it takes for half of the substance to decay
14 years ago
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OpenStudy (anonymous):
what are you choices?
14 years ago
OpenStudy (anonymous):
ok never mind haha thanks guys!
14 years ago
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