The decay of a particular radioactive substance is given by the formula----UPLOADED----where t is the time it takes for half of the substance to decay, and N(0) is the initial amount of the substance. Find the half-life of this substance to the nearest thousandth of a year.
\[\frac{1}{2}N_{0}=N_{0}e^{-1.8t}\implies e^{-1.8t}=\frac{1}{2}\implies-1.8t=\ln (\frac{1}{2})\implies t=-\frac{\ln(\frac{1}{2})}{1.8}\approx0.385\]
answer is 0?
to the nearest thousandth means 3 places to the right of the decimal.
so wht does that meant to the proble im not getting the right answer
no, it means the answer as bendt stated above is 0.385
so thaat answer that is not a choice it is multiple choice
in the given equation t is in what units?
time right
----where t is the time it takes for half of the substance to decay
what are you choices?
ok never mind haha thanks guys!
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