Question

The amount of carbon-14 still present in a sample after t years is given by the function
where C0 is the initial amount. Estimate the age of a sample of wood discovered by an archeologist if the carbon level in the sample is only 29% of its original carbon-14 level

Answer 1

it is given that C(t) = 0.29 C0
find t.

Answer 2

how

Answer 3

0.29 C0 = C0e^-0.00012t
find t.
do some arithmetic manipulation

Answer 4

ok i get -1.237=.9998 now wht

Answer 5

you did something wrong. check your answer.

Answer 6

.29=.9998?

Answer 7

could you solve so i can check it out to do the others

Answer 8

nope. under no circumstances is 0.29 = 0.9998
its like saying 2 = 3
keep in mind that you are solving for t.

Answer 9

no I cannot solve your problem for you. I will only show you how to do your problem. I notice that you have already been shown how to solve a similar problem.

Answer 10

i did not plug in variable cuz i did not want to type it that slow

Answer 11

yeah but not like this it was a half life problem this is not like that one

Answer 12

it follows a similar pattern. you can do this. try :)

Answer 13

.29c0=.9998(t)
then wht

Answer 14

\[0.29C_0 = C_0e ^{-0.00012t} \rightarrow 0.29 = e^{-0.00012t}\]
solve for t.
you did something wrong.

Answer 15

i did e^-.00012

Answer 16

so that should be \[0.29 = 0.9998^t\], not .29c0=.9998(t)

Answer 17

o ya so then wht do i do

Answer 18

take log on both sides

Answer 19

s00

-.537c0=.000086^t

Answer 20

?

Answer 21

why is there a c0 in your equation?

Answer 22

and why is the t an exponent? do you know how logarithms work?

Answer 23

i dont know

Answer 24

also, do you know basic arithmetic manipulation?

Answer 25

i dont know wht all this is but i could doo all the rest it you could just do wht most ppl do and show your work and do it si i can see it

Answer 26

sorry. it doesn't work that way. maybe "most people" can show you how its done.

Answer 27

wht u mean that is the best way...wht u think teachers do when u have question they work it out with you and show u the steps, plus i can look at it to do otheers

Answer 28

you have already been shown how to do a problem with is almost exactly the same as this one. also, my methods are my methods. too bad you don't like them. sorry :)

Answer 29

ok well u are supposed to adapt to the students needs not say well to bad learn somewhere else bud

Answer 30

oh well. you are supposed to learn from similar problems. you do that and I will follow your lead :)

Answer 31

did i ask a similer one because it does not look that similer to me cuz i need help with this, and im wasting time that i could know how to do it and be doing all the other ones like this

Answer 32

okay. lets see. what happened when you took log on both sides of the equation
\[0.29 = 0.9998^t\]

Answer 33

post what you get when you do that.

Answer 34

-.537c0=.000086^t

Answer 35

how are you getting a c0 when none existed before?
log 0.29 = log 0.9998^t
log 0.29 = t log 0.998 (since we know that log a^b = b log a)

Answer 36

ok no co is it good?

Answer 37

ya

Answer 38

find t from what I posted.

Answer 39

i solved it but i know it is wrong

Answer 40

answer options 10,316
20,632
10,216
12,286
None of the above

Answer 41

what was the answer you got? I got 6188 time units.

Answer 42

sorry I got 10315.61

Answer 43

sorry went to bed

Answer 44

how u geet that answer

Answer 45

do not round off e^-0.00012 to 0.9998. you will get an incorrect answer.
type in log 0.29/ log (e^-0.00012) into google and press enter

Answer 46

\[0.29C_0 = C_0 e ^{-0.00012t}\]
cancel C0 on both sides giving you \[0.29 = e ^{-0.00012t}\]
take the natural log on both sides giving you\[\ln 0.29 = -0.00012t\]
then t = (ln0.29/(-0.00012))