Question

I need help resolving the equation by the method of factorisation:

3x^2+5x + 2 = 0

I thought it was x(2x+4) 1(x+1)
x=-4 and x=-1

But it gives me 2x^2 + 5x + 1

Help? :)

Answer 1

(x+1)(3x+2)

Answer 2

(3x + 2 )(x + 1 )

Answer 3

@serrico
do u know how the factorisation method works???

Answer 4

Sorry it was meant to be 2x^2+5x + 2 = 0

@Harkirat, I do is just this question, I have to multiply 2x x 2 = 4 and two numbers that add up to 5 is 4 and 1

Answer 5

correct u hv to fist take the product of the coefficient of x^2 and the constant
here it is 2 x 2 = 4
Now u hv to split 4 into two factors so that their sum is 5
u hv rightly chose 1 and 4 because 1x4 = 4 and 1+5 = 5

Answer 6

2x^2 + 5x + 2 = 0
2x^2 + 4x + 1x + 2 = 0
2x(x + 2) +1(x + 2) = 0 here u hv to ensure that terms inside bracket r same and do not have any common factors)
so
(2x + 1)(x+2) = 0
if 2x + 1 = 0 ==> x = -1/2
if x + 2 = 0 ==> x = -2

so yr roots are x = -1/2 , -2

Answer 7

to show u your mistake, I hv copied a part of yr answer you wrote above

"I thought it was x(2x+4) 1(x+1) <------ Mistake here. In first bracket 2 is common in 2x and 4 and so has to be taken out

Answer 8

is it clear now?????????

if so, pls click GOOD ANSWER button for me ☺

Answer 9

Thank you very much, don't worry I was going to do that I was just waiting until you finished typing and read what you wrote and I understood very clearly.

Thank you Harkirat, just what I needed ;)

Answer 10

u r welcome :)