The length of a rectangle is 2 more than three times the width. The area of the rectangle is 161 square inches. What are the dimensions of the rectangle?

If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?

Question

The length of a rectangle is 2 more than three times the width. The area of the rectangle is 161 square inches. What are the dimensions of the rectangle?

If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?

myininaya · Answer

width=x
length=l
l=2+3x
area=A
A=161=lx
lx=161
(2+3x)x=161
2x+3x^2=161
3x^2+2x-161=0 solve this for x and you will have width
then just plug that x into l=2+3x to find length

myininaya · Answer

only take positive values of 3x^2+2x-161=0