Question

Divide,
(9x^3-18x+11)divided by (3x-3)

Answer 1

\[(9x^3-18x+1) \div(3x-3)\]

Answer 2

http://tutorial.math.lamar.edu/Classes/Alg/DividingPolynomials.aspx There are plenty of examples there.

Answer 3

that still doent help

Answer 4

cant you help me get the answer \

Answer 5

We can do a short twiddla meeting if you'd like. http://www.twiddla.com/564999

Answer 6

okay

Answer 7

im in

Answer 8

(3x-3)(3x^2+3x-3) & 2 left

Answer 9

Here is a summary of what we did on the twiddla board.

Answer 10

so whats the answer then ?

Answer 11

mathteacher made a mistake....

Answer 12

ok

Answer 13

ok

Answer 14

Where did I go wrong?

Answer 15

thats not an option

Answer 16

what should be it
?

Answer 17

I just posted it

Answer 18

What are the answer choices?

Answer 19

where did u post it?

Answer 20

Oh. My. goodness. I solved the wrong problem. Your original problem ended with +11, and I wrote +1 at the end. :(

Sorry. Hopefully, the twiddla session was helpful, the techniques we used were the same.

Answer 21

final answer:
(3x^2+3x-3) & 2 left

Answer 22

lol, inik got it

Answer 23

it should be right... check:
(3x^2+3x-3)(3x-3)=9x^2 -18x+9
on original +11, so only 2 is the difference
right?

Answer 24

so its the first answer option i posted then?

Answer 25

It's the second answer choice

Answer 26

ok r u sure?

Answer 27

Yes, 100% positive

Answer 28

The remainder is 2, so the answer should be
\[3 x ^{2} + 3 x - 3 + 2/(3x - 3).\]