Question

log(x-4) - logx = 2log3

Answer 1

I got -1/2 but that's not right

Answer 2

\[log(x-4)-log(x)=2log(3)\]
\[log(\frac{x-4}{x})=\log(3^2)\]

Answer 3

\[\frac{x-4}{x}=3^2\]

Answer 4

\[x-4=9x\]

Answer 5

\[\frac{x-4}{x}=9\]
\[x-4=9x\]
\[8x=-4\]
\[x=-\frac{1}{2}\]
which certainly isn't right because you cannot take the log of a negative number

Answer 6

no solution!

Answer 7

or say no real solution

Answer 8

\[\color{blue}{\text{ so i guess there is no solution}}\]

Answer 9

no so you know there is no real solution

Answer 10

\[\color{#FF0088}{\text{ in this color}}\]

Answer 11

okay that's what I thought, thanks XD