log (x+12) + log x = 6
\[\log(x(x+12))=6\]
\[x^2+12x=10^6\] and now you are on your own because i have no idea what he answers are
\[\color{yellow}{\text{myininaya does though}}\]
its hard to read your yellow
\[\color{blue}{\text{blue is better}}\]
\[\color{blue}{\text{can you solve this problem?}}\]
\[x^2+12x-1000000=0\] did i put in 6 zeros i cant tell thats too many zeros
\[x=\frac{-12 \pm \sqrt{144-4(-1000000)}}{2}\]
maybe it was a .... typo!
yeah i could have done that.
\[x=\frac{-12 \pm \sqrt{144+4000000}}{2}\]
\[x=\frac{-12 \pm \sqrt{4000144}}{2}\]
ok enough algebra for one night. do you know that last night some guy was trying to use linear approximation to a trig function IN DEGREES!
question was use linear approximation to find \[\sin(44)\]!
what kind of morons do they have teaching mathematics?
i actually logged out, and then came back and logged in to tell the guy that he could not do it
lol satellite i didn't realized we changed the subject
oh i was just ranting. but really i was plucked
i see a lot of idiotic questions here but that one took the cake
then there was another problem form some idiots at "apex learning" whatever that is, that wanted the students so say the line went "down and to the left"!
\[x=\frac{-12 \pm \sqrt{16}*\sqrt{250009}}{2}=\frac{-12 \pm 4 \sqrt{250009}}{2}=-6 \pm 2\sqrt{250009}\]
ok show off. bet the question was something else. i am off to take the derivative of a trig function of degrees. i'll let you know what i get
hey autuumn the only solution you have -6+2sqrt{250009{
but i now one damn thing for sure. the derivative of sine is NOT cosine. gnight
lol what?
satellite have you gone mad?
eh okay thanks everyone :)
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