An overhead hoist accelerates a 10 kg at 2 m/s^2 over a vertical distance of 1 m. What is the tension in the single cable attached to the 10 kg mass?

Question

anonymous · Answer

The tension is the apparent weight... mg is down, T is up, a is up... then$$a = (\sum F)/m = (T - mg)/m$$ or $$T = m(g+a)$$Solve for T

anonymous · Answer

So I understand that I'm to solve for T.
But I am curious as to how I should set up the equation.
What I mean is I believe that m = 10 kg, a = 9.8, but I do not understand what should go in place for the 'g'. Where does the distance of 1m come into play? That's also throwing me off a bit.

anonymous · Answer

a = 2 m/s^2, g = 9.8 m/s^2, distance is to throw you off

anonymous · Answer

Ohhhh okay. I understand now. Thank-you! You have been very helpful thus far and not with just this question but others. I am currently taking an online physics class and I've never had physics before and I need to learn somehow. So thank-you again for being a teacher in a way lol.