Question

use factoring to find the zeros of each equation y=x^2+18x+81

Answer 1

if looking for a zero, first set y=0 so 0 = x²+18x+81 . Then, try to get it in the form of 0 = (x +-a)(x+-b) Hint: your equation represents a binomial theorem.

Answer 2

\[y=x^2+18+81\]
1*81=81
find two numbers such that when u multiply u get 81 and when u add u get 18
the two numbers are 9 and 9
\[y=x^2+9x+9x+81\]
\[x(x+9) 9(x+9)\]
\[(x+9) (x+9)\]=0

x=-9