Question

write the standard form of the equation of the circle with endpoints of a diameter with the points (1,8) and (-3,11)

Answer 1

center is the midpoint of the line joining the two points. midpoint is
\[(\frac{1-3}{2},\frac{8+11}{2})\]
\[(-1,\frac{19}{2})\]

Answer 2

lalaly will complete it

Answer 3

find the mid point
x= (1+-3)/2=-1
y=(8+11)/2=19/2

find the distance
squareroot of (-3-8)^2+(11-8)^2 = sqrt of 121+9= square root of 130
so radius is (squareroot of 130)/2
equation is

(x+1)^2+(y-19/2)^2=130/4

Answer 4

thank you!

Answer 5

;);)