Question

Quick question to clarify my understanding of how to find the gradient of a function: In practice exam 2b, Problem #1: (x^2)(y^2)-x

Answer 1

all right, to find the gradient of this function, \[f(x,y) = x^2y^2-x\]

Answer 2

you find the partial derivative of f with regard to x, and then with regard to y

Answer 3

\[<\partial f/\partial x, \partial f/\partial y>\]

Answer 4

all right, so first, partial w/re to x is 2x*y^2-1

Answer 5

and partial w/re to y is 2x^2*y

Answer 6

looks good, so format would be: \[<2xy^2-1, 2x^2y>\]

Answer 7

right, excellent, just wanted to make sure my brain was working properly ;)

Answer 8

now you can just plug in the point to consider like in the prac. exam problem

Answer 9

idk.