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Solve the limit algebraically limx->1 (x^3-1)/(x-1) i just want to check to see if i am doing the right thing because my algebra is rusty
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\[\frac{(x-1)(x^2+x+1)}{x-1}\] so the x-1 cancels
and were left with \[x^2+x+1\]
which is 3
thats right.... the lim of that is 3 ... yaaah
yay! lol...
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thanks lalaly
;) no problem :D:D
x^3-1^3/x-1=3x^2
cannot solve by finding the derivative lol...
the answer is \[3x ^{2}\]
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by the derivative rules..
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