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Mathematics 15 Online
OpenStudy (anonymous):

triple integral help

OpenStudy (anonymous):

OpenStudy (anonymous):

Please help, I'm having trouble even starting this one.

OpenStudy (amistre64):

z = [x,1] y = [(1-x),1] x = [0,1] sketch it on the xyz axis stuff right?

OpenStudy (amistre64):

maybe like this?

OpenStudy (amistre64):

order x,y,z x = [(1-y),1] y = [(1-z),1] z = [0,1] if i see it right :)

OpenStudy (amistre64):

order y,x,z y = [(1-x),1] x = [z,1] z = [0,1] maybe?

OpenStudy (anonymous):

I think you've almost got it with that graph, though I think the non-shaded region is the one you're working on..

OpenStudy (amistre64):

i do admit i need more practice :)

OpenStudy (amistre64):

not bad :) I interpret the base as shading from y = -x+1 to y = 1 :)

OpenStudy (amistre64):

in some axis along tis construct z | / \ x y

OpenStudy (amistre64):

my z is off; i got it from 0 to x :)

OpenStudy (anonymous):

thanks for all the help guys! I gotta see if I can pull all this together, brb

OpenStudy (amistre64):

perhaps more atuned to this? :)

OpenStudy (amistre64):

ugh .... i messed up the y = 1-x on that one; thats y=x lol

OpenStudy (anonymous):

Yeah.

OpenStudy (amistre64):

this is my final answer :) im 34% sure this is accurate lol

OpenStudy (anonymous):

Maybe like this?

OpenStudy (anonymous):

yep, that's it exactly. Just realized myself that if y = 1-x and x = z then y must equal 1-z.

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