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Mathematics 15 Online
OpenStudy (anonymous):

Use the given graph to estimate the value of each derivative. (Round all answers to one decimal place.) f'(0) f'(1) f'(2) f'(3) f'(4) f'(5)

OpenStudy (anonymous):

OpenStudy (anonymous):

\[f'(1)=0\] because the line tangent to the graph would be horizontal (slope = 0 ) there. likewise for \[f'(4)\]

OpenStudy (anonymous):

\[f'(0)\] is some negative number because the tangent line has a negative slope. you have to estimate. put a ruler on the paper, make it tangent to the graph at that point and then ignore the curve and find the slope of the ruler. i would guess at -2

OpenStudy (anonymous):

same procedure for the rest. i would estimate \[f'(2)=1\]

OpenStudy (anonymous):

hello sattllite how are you? I was looking for you when it was time to study for my test...but you never came back online

OpenStudy (anonymous):

how was the test? sometimes i eat, sleep, drink beer...

OpenStudy (anonymous):

the test was horrible!!!! I am studying earlier to do better on EXAM 2

OpenStudy (anonymous):

ok i got: f'(0) f'(1) f'(2) f'(4) How do I get: f'(3) f'(5)

OpenStudy (anonymous):

let me look

OpenStudy (anonymous):

hard to tell exactly. clearly it is positive. really a ruler is the best way, but i would say probably \[f'(3)=1\]

OpenStudy (anonymous):

I really dont understand how to do this problem..

OpenStudy (anonymous):

and \[f'(5)\] is negative because the tangent like would be heading down. maybe \[-\frac{1}{2}\]

OpenStudy (anonymous):

site is really slow. do you know what i mean when i say "line tangent to the graph of the curve"?

OpenStudy (anonymous):

f'(3) isnt 1

OpenStudy (anonymous):

well maybe it is a little bigger than one

OpenStudy (anonymous):

take a ruler, put it on the paper like in the picture i sent. if you make the ruler tangent at x = 3, and then look only at the slope of the ruler, that will give you the answer

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