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Mathematics 17 Online
OpenStudy (anonymous):

What about this with variables?! Factor the expression completely. (a^2 + 2a)^2 − 2(a^2 + 2a) − 3

OpenStudy (anonymous):

take a^2 + 2a = t u get t^2 -2t -3 t^2 - 3t + t - 3 t(t-3) + (t-3) (t+1)(t-3) now replace t

OpenStudy (anonymous):

im not understanding what u mean

OpenStudy (anonymous):

which part dont u get?

OpenStudy (anonymous):

adding the t. it doesnt make sense what does it come out to when u factor it completely.

OpenStudy (anonymous):

?

OpenStudy (anonymous):

him 1618 do you know what it comes out to ?

OpenStudy (anonymous):

(a^2 + 2a + 1)(a^2 + 2a -3)

OpenStudy (anonymous):

Let u=a^2+2a Now substitute this u in everywhere you have an a^2+2a: u^2-2u-3 Factor this with respect to u: (u-3)(u+1) Now we've factored for u, but the problem asked us to factor for a, so we need to plug a^2+2a everywhere we have a u: (a^2+2a-3)(a^2+2a+1) Now, we can factor each of these further: (a+3)(a-1)(a+1)(a+1)

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