Question

How do I solve
ln(-x) +ln3=ln(2x-15)

Answer 1

use this property to combine the ln's on the left side of the equation:
\[\ln(a)+\ln(b) = \ln(a*b)\]

Answer 2

Thus the left side of your equation becomes:
\[\ln(-x)+\ln(3)=\ln(-3x)\]
Now that your equation look like this:
\[\ln(-3x)= \ln(2x-15)\]
get rid of the ln's, and you have:
-3x = 2x - 15
-5x = -15
x = 3

Answer 3

Just not sure if there is an actual solution since solving for 3 ends up with ln of a negative number on both sides.

Answer 4

there is no real solution