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Find the area of the curve between y=3-x^2 and y=2x.
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\[\int\limits_{-3}^{1} (3-x^2) - (2x) dx\]
should get 32/3
the limits came from find the intersection of the equations 3-x^2=2x put the top function first and then - the bottom function
and then integrate and plug in limits using funadmental thm of cal
so if i got 32/3, i got the answer right??
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well thats what i got assuming i didnt make a mistake
ok i see :)
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