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solve the inequality. graph the solution set and write it in interval notation. -9 \[\le\] -2x + 5 < 1 Is it (7, infty) or the other way around.
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\[-9\le-2x+5<1\]?
yes that is correct
i just started using this so Im still trying to fig out how to use some of the signs...
\[-9-5\le-2x<1-5\]\[-14\le-2x<-4\]\[\frac{-14}{-2}\le x<\frac{-4}{-2}\]\[14\ge x>2\]\[(2,\infty)\]?
the last one I was wrong
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wouldnt you divide the 2 over the 14 to get 7 or am I way off...
I caculator wrong
\[7\ge x>2\]
you r rite... I was looking at the graph wrong
−9−5≤−2x+5-5<1−5 −14≤−2x<−4 −14/2 ≤ -x < −4/2 −7≤-x<−2 \[7 \ge x > 2\] or 2<x≤7 \[ x \in ]2,7] \]
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|x|x>2 , x<=2|
no infty
got it.... thank you both very much
ty
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