consider the function f(x) = {(sinx)/x, x cannot equal 0 {k, , x = 0 In order for f(x) to be continuous at x - 0, the value of k must be...
We have that \[\lim_{x \rightarrow 0} (\sin x)/x =1\] (This is a common result; I'm sure you can find a proof of it somewhere on Google if you need to) Now in order for a function to be continuous at 0, we require that \[\lim_{x \rightarrow 0} f(x) =f(0)\] It's pretty clear that the only k for which this is true is k=1.
sorry, just slightly confused on the end about the k
Zid's got it exactly right. In order for a function to be continuous, the value of the function at every point has to be equal to the value of the limit as x approaches that point. Thus, since \[\lim_{x \rightarrow 0} \sin(x)/x = 1\], we pick k to be 1 so that at x=0, f(x) = 1.
ok, that makes sense.
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