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OpenStudy (anonymous):
yet another question...
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OpenStudy (anonymous):
OpenStudy (blacksteel):
Alright, this one isn't too bad. Let's start by rewriting |f(x) - 7| as |3x + 1 - 7|, or |3x - 6|, or 3*|x-2| (since 3 is positive, we can do this). Using, e for epsilon and d for delta, 3*|x-2| < e whenever |x-2| < e/3. Thus, the correct answer is A, since if |x-2| < e/4, it is less than e/3.
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