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please help! i need to solve for x in the problem: 3^(2x)-2*3^(x+5) + 3^10 =0
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\[3^{2x}-2*3^{x+5} + 3^{10} = 0\] Is it right?
yes, hope so
yeh thats how its written
x=5
3^x=t t^2-2*3^5t+3^10=0
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So then do I combine the "-2*3^5t ?"
just complete the square and you'll get (t-3^5)^2=0
ok thank you
i think i need help with the steps?
please?
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Like uzma said use a substitution t=3^x. First notice that 3^(x+5)=(3^x)*(3^5)=(3^5)*y. Then the equation reduces to t^2-2(3^5)y+3^10=0. Then solve this as a quadratic in y, using 'complete the square'. Make sense?
I used y so when you see y think of it as t
before i complete the square do i simplify to t^2-6^5t+3^10?
oh i get it thank you
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