Question

6 + 7 * log2 x = 14
with 2 being the base of the log

Answer 1

subtract 6 from both sides\[6 - 6 + 7*\log2 x = 14 - 6\]
Divide 7 on both sides\[(7 * \log2 x )/7= 8/7\]
This gives \[\log 2 x = 8/7\]

If 2 is the base of the log, than x will equal the base of the log to an exponent.\[2^(8/7) = x\]