Question

find the particular antiderivative that satisfies the following conditions: p(prime)(x)=70/(x^3) and p(2)=4

Answer 1

\[70\int x^{-3}dx \]

Answer 2

but then p(2) is not giving me 4

Answer 3

\[F(x)=-\frac{35}{x^2}\]

Answer 4

+C

Answer 5

the antiderivative is

\[P(x)=-35x^{-2}+c\] now put
\[P(2)=-\frac{35}{2^2}+c=4\] and solve for c

Answer 6

yeps; this thing is slooowwww today.

Answer 7

slow slow slow. i don 't even see the latex i wrote

Answer 8

lol oh I see thanks!

Answer 9

did you get that? you solve for the constant by the information given. i can't seem to write it

Answer 10

\[P(x)=-35x^{-2}+c\] now put
\[P(2)=-\frac{35}{2^2}+c=4\] and solve for c

Answer 11

ok forget it. i'm out